# A brief illustration of Later proofs affirming Pythagoras Theorem

Let us assume that we have a perfect square of sides (a + b) units and an inscribed square of sides c units.

We can express the area of the interior square in two different ways;

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Area of square = c2Â square units. Or,

Area of square = area of the big square â€“ area of the region not taken by the small

Square.

= (a + b)2Â â€“ Â½ of4(ab)

= a2Â + 2ab +b2Â â€“ 2ab

= a2Â + b2Â square units.

Therefore, since the two algebraic expressions represent the area of the same plain figure; theyÂ mustÂ be equal, c2Â = a2Â + b2, proving Pythagoras theorem (Khalaf, 1996, p. 1).

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